14x^2-14x-95=0

Solution for 14x^2-14x-95=0 equation:

14x^2-14x-95=0

a = 14; b = -14; c = -95;
Δ = b2-4ac
Δ = -142-4·14·(-95)
Δ = 5516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5516}=\sqrt{4*1379}=\sqrt{4}*\sqrt{1379}=2\sqrt{1379}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-2\sqrt{1379}}{2*14}=\frac{14-2\sqrt{1379}}{28}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+2\sqrt{1379}}{2*14}=\frac{14+2\sqrt{1379}}{28}
$